Bài 1.32 trang 9 sách bài tập (SBT) Hóa học 12

Viết các phương trình hoá học để hoàn thành các dãy biến hoá sau :

a) \({\rm{ }}{C_2}{H_4} \to C{H_3}CHO\buildrel {B{r_2},{H_2}O} \over
\longrightarrow A\buildrel { + B} \over
\longrightarrow {C_4}{H_8}{O_2}\buildrel {LiAl{H_4},{\rm{ }}{t^0}} \over
\longrightarrow B\)

b) CH₃CH₂COOH→CH₃CHBrCOOH→CH₂=CHCOOK→ CH₂=CHCOOH →CH₂=CHCOOCH₃ →polime

c)CH₂=CH₂→CH₃CHO→CH₃COOH→CH₃COOCH=CH₂→polime 1→ polime 2

Hướng dẫn trả lời:

a)

\(2C{H_2} = C{H_2} + {\rm{ }}{O_2}\buildrel {{t^0},xt} \over
\longrightarrow {\rm{ }}2C{H_3} - CHO\)

CH₃-CHO + Br₂ +H₂O → CH₃-COOH + 2HBr

CH₃-COOH + C₂H₅OH ↔ CH₃COOC₂H₅ + H₂O 

\(C{H_3}COO{C_2}{H_5}\buildrel {LiAl{H_4},{\rm{ }}{t^0}} \over
\longrightarrow 2C{H_3}C{H_2}OH\)

b) 

\(C{H_3}C{H_2}COOH + B{r_2}\buildrel {{t^0}} \over
\longrightarrow C{H_3}CHBrCOOH + HBr\)

\(C{H_3}CHBrCOOH + 2KOH\buildrel {{C_2}{H_5}OH,{\rm{ }}{t^0}} \over
\longrightarrow C{H_2} = CHCOOK + KBr + 2{H_2}O\)

\(C{H_2} = CHCOOH + C{H_3}OH\buildrel {{t^0},{\rm{ }}{H_2}S{O_4}\left( \right)} \over
\longrightarrow C{H_2} = CHCOOC{H_3} + {H_2}O\)

\(nC{H_2} = CHCOOC{H_3}\buildrel {{t^0},xt,p} \over
\longrightarrow - {(C{H_2} - CH - COOC{H_3})_n} - \)

c) \(2C{H_2} = C{H_2} + {\rm{ }}{O_2}\buildrel {{t^0},xt} \over
\longrightarrow {\rm{ }}2C{H_3} - CHO\)

\(C{H_3}COOH + C{H_2} = CH - OH\buildrel {{t^0},{\rm{ }}{H_2}S{O_4}\left( \right)} \over
\longrightarrow C{H_3}COOCH = C{H_2} + {H_2}O\)

\(nC{H_3}COOCH = C{H_2}\buildrel {{t^0},xt,p} \over
\longrightarrow - \left( {C{H_2} - CH - OCOC{H_3}} \right){ - _n}\).

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